[Music] Adekunle Gold Ft. Simi – No Forget

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2016 Ondo State Joint Exam Government Obj & Essay Questions And Answers Now Available For Free

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VERIFIED GOVERNMENT OBJ ANSWER:
.1-10: DACDCCADCC
11-20: BBBBCCDCAB
21-30: BDAACABDCA
31-40: CCCBCCCABC
41-50: BDCDDCDCBC

(1A)
Government as an art of governing is process of
running the activities of a state by ensuring
orderliness among the citizens


(1B)
(i)LAW:- it is the responsibility of the
government to make law enforce it and
interprets to it citizens for proper conduct
(ii)PROVISION OF SOCIAL AMENITIES:-
Government provided social amenities for it
citizens such as good road,pipe-
bornwater,electricity, good health care e.t.c
(iii)DEFENCE:- Another function of government
is that they defence their territory against any
external force or attack it also ansure maximum
security within its territory in order to protect
the life and properties of its citizens


(3A)
constitution can be defined as a body of rule and
regulations which state how a country should
be governed.It can also be defined as
an embodiment of principle rule and act through
which a system of government in any country
is stipulated


(3B)
(i)written constitution
(ii)unwritten constitution
(iii)rigid constitution


(3C)
(i) written constitution is codified into one
single document and it allow for reference
(ii) it is not easy to ammend or change without
2/3rd majority of the house
(iii)it is documented and easy to retrieved.


(8A)
Local government can be defined as a
government or system of government at grass
root level that overseas the affairs of the people
at the lacal level by bringing the dividend of
government to them


(8B)
(i)By laws:- Government at the local level make
by law for their people to guide their code of
conduct e.g environment sanitation
(ii) provision and construction of motor park and
market at the grassroot level.
(iii) construction and mentanance of toed at the
local level.


PROBLEMS
(i)Lack of adequate capital /fund to carry out
visible or capital project at the local level.
(ii)administrative problem: poor management of
available resources by the administrative body at
grass level is another problems affected local
government in Nigeria
(iii) corruption: corruption practice among the
top official by embenzle the allocation fund

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2016 Ondo State Joint Exam Chemistry Obj & Essay Questions And Answers Now Available For Free

CHEMISTRY ANSWERS



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PLEASE USE THIS ANSWER
CHEM-OBJ
1-10: BCBBCCCBBB
11-20: BAADBADDAB
21-30: BABABAAADB
31-40: CCBBADBDDC
(1A)
DALTON Law Of pressure
It states that at a particular temperature,
the total pressure of
a mixture of two or more non-interacting
(ideal) gases is
equal to the sum of partial pressures of
the individual gases.
Mathematically, it can be written as: Ptotal
= P1 + P2 + P3 + ...
where P1, P2, P3, etc. are the partial
pressures of each
component of the mixture.
(1B)
LOADING
(1C)
I. Aluminum Oxide.
It forms a thin oxide coating (Al2O3)
almost instantly on exposure to air and
that coating prevents
further reaction with the metal, thus
making the world safe
for soda and beer cans (not to mention
beer kegs!).
ii. Sodium Metal
Sodium is an alkali metal, and chlorine is a
halogen. This
means that sodium contains one electron
in its outer orbital
and chlorine contains seven electrons in its
outer orbital.
iii. sodium hydroxide
The species, [Al(OH)4]- is the
tetrahydroxoaluminate complex
ion. It only appears at high pH.
==============+======++=
++===================
2A
ALKALI COMPOUNDS
Common name | Chemical name | Formula
Barite Barium | sulfate | BaSO4
Epsom salts |magnesium sulfate | MgSO4
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2016 Ondo State Joint Exam Mathematics Obj & Essay Questions And Answers Now Available For Free

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MATHEMATICS-OBJ
1-10: DCCADCBBAB
11-20: DCADBCBDAC
21-30: BDAADBCBBA
31-40: DABDCABDCA


VERIFY MATHEMATICS THEORY ANSWER
SECTION A: (30 Marks)
INSTRUCTION:Answer all questions. All Questions carry equal marks.

(1a)
1011.1012= 13021110. 1-10-21-3
= (1*23)+(0*22)+(1*21)+(1*20)+(1*2-1)+(1*2-2)+(1*2-3)
= (1*8) + (0*4) + (1*2) + (1*1) + (1*1/2) + (0*1/4) + (1*1/8)
= 8 + 0 + 2 + 1 + 1/2 + 0 + 1/8
= 11 + 1/2 + 1/8 = 88 + 4 + 1/8 = 93/8 = 11.625
1011.1012= 11.62510
∴ 1011.101two= 11.625ten

(b)
Draw The Table in Row & Column Like The Question..
|(x)| 0 | 1 | 2 | 3 | 4 |
| 0 | 0 | 0 | 0 | 0 | 0 |
| 1 | 0 | 1 | 2 | 3 | 4 |
| 2 | 0 | 2 | 4 | 1 | 3 |
| 3 | 0 | 3 | 1 | 4 | 2 |
| 4 | 0 | 4 | 3 | 2 | 1 |

••••••••••••••••••••••••••••••••• •••

(2a)
Solve 4r – 3/6r + 1 = 2r – 1/3r + 4
Cross Multiply
(4r – 3)(3r + 4) = (2r – 1) (6r + 1)
12r2+ 16r – 9r – 12 = 12r2+ 2r – 6r – 1
12r2+ 7r – 12 = 12r2– 4r -1
12r2– 12r2+ 7r + 4r = -1 + 12
11r = 11
Divide both sides by 11
11r/11 = 11/11
r = 1Ans…

(b)
Sn= n/2 [2a + (n -1)d]
S9= 9/2 [2a + (a-1)d] = 72
S9= 9/2 [2a + 8d] = 72
Next four terms = 71
S13= 13/2 [2a + (13-1)d] = 72 + 71
13/2 [2a + 12d] = 143
S9=> 18a + 72d = 144 ——– (eqn i) a + 4d =8
S13=> 26a + 156d = 286 ——-(eqn ii) a + 6d = 11
Subtract

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(3a)
Solve 9(x-3)= 27(x-5)
32 (x-3)= 33 (x-5)
2(x-3) = 3(x-5)
2x-6 = 3x-15
-6 + 15 = 3x -2x
9 = x
x = 9Ans…

(b)
U = { all integers}. = {…,-3,-2,-1,0,1,2,3,…}
P = {x:x ≤0}. = {…,-3,-2,-1,0}.
R = {x:-2 ≤x <7 16p2="" 4p="" a2="-x2" a="" and="" both="" by="" cross="" divide="" express="" given="" in="" m.="" m2="" m="" multiply="" of="" p="" pi="" ri="{1,2,3,…]" sides="" square="" terms="" that="" to="" x2="" x=""> x2= 16P2/m2+ a2
x2= a2– 16P2/m2
x=m√a2– 16P2/m2
=a – 4P/m = am – 4P/m
x = am – 4P/m

(b)
True Table for ∽ (P ⋀ ∽ q)
p q ∽q p⋀∽ ∽(p p⋀

••••••••••••••••••••••••••••••••• •••


(5)
Let income be = x
1/8 of x = x/8 on tax free
(7/8 * 20/100)x = 7/40x
x/8 + 7x/40 + 49000 = x
5x + 7x + 1,960,000/40 = x
5x + 7x + 1,960,000 = 40x
1,960,000 = 40x – 12x
1,960,000 = 28x
Divide both sides by 28
1,960,000/28 28x/8
x = #70,000
∴ The tax payer`s income is #70,000

SECTION B: (50 Marks)
INSTRUCTION:Answer any five (5) questions from this section. All Questions carry equal marks.

(6a)
nth term = a + (n-1)d
4th term = a + (4-1)d = a+3d = -3
9th term = a + (9-1)d = a+8d = 12
Let a+3d = -3 —————— (eqn i)
a+8d = 12 —————— (eqn ii)
Subtract eqn ii from eqn i
3d – 8d = -3 – 12
-5d = -15
d = -15/-5
d = 3.
sum of the first seven terms
Snn/2 [2a+(n-1)d]
where n = 7, d = 3, a = -12
Sn7/2 [2(-12) + (7-1)(3)]
= 7/2 [-24 + 18]
= 7/2 [-6] = -42/2 = -21
Sketch the Circle

{8}
To get the value of n.
543n= 244n+ 255n
5*n2+ 4*n + 3*no= 2*n2+ 4*n + 4*no+ 2*n2+ 5*n + 5*no
5n2+ 4n + 3 = 2n2+ 4n + 2n25n + 5
5n2+ 4n + 3 = 4n2+9n + 9
5n2– 4n2+ 4n – 9n + 3 – 9 = 0
n2– 5n – 6 = 0
n2+ n -6n – 6 = 0
n(n+1) -6 (n+1) = 0
(n+1)(n-6) = 0
n = -1 or 6
n = 6
(b)
Sketch out the Triangle
Cos65o= h/25
=> 25 cos 65o= h
h = 25 (0.4226)
h = 10.5650
h = 10.6 (1 d.p)


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